-35x=35x^2

Solution for -35x=35x^2 equation:

-35x=35x^2

We move all terms to the left:

-35x-(35x^2)=0

determiningTheFunctionDomain
-35x^2-35x=0

a = -35; b = -35; c = 0;
Δ = b2-4ac
Δ = -352-4·(-35)·0
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1225}=35$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-35)-35}{2*-35}=\frac{0}{-70}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-35)+35}{2*-35}=\frac{70}{-70}
=-1
$